Two cyclists leave town at the same time on the same road going in  the same direction. Cyclist a is going 6 miles per hour faster than cyclist b. After 8 hours, cyclist a has traveled three times the distance as cyclist b. Use the equation 24x= 8(x+6) to find how fast cyclist b was traveling.

• rapatel1: 24x=8x+48
  16x=48
  /16  /16
  
  x=3
• isyllus:

  Answer:

  3 mph

  Step-by-step explanation:

  Two cyclists leave town at the same time on the same road going in  the same direction.

  Cyclist A is going 6 mph faster than cyclist B

  Let speed of cyclist B be x mph

  Speed of cyclist A be (x+6) mph

  Both cyclist leave town at the same time and traveled 8 hours.  

  • Distance covered by cyclist A in 8 hours= 8(x+6)
  • Distance covered by cyclist B in 8 hours= 8x

  After 8 hours cyclist A has traveled 3 times the distance as cyclist B

  Therefore, 8(x+6) = 3(8x)

  8x + 48 = 24x

  24x - 8x = 48

         16x = 48

            x = 3 mph

  Hence, The speed of cyclist B was 3 mph