a player gets to throw 4 darts at the target shown. Assuming the player will always hit the target, the probability of hitting an odd number three times is *blank* times more than the probability of hitting an even number 3 times

• JeanaShupp:

  Answer: The probability of hitting an odd number three times is [tex]3\dfrac{3}{8}[/tex] times more than the probability of hitting an even number 3 times.

  Step-by-step explanation:

  From the given picture , the total total number of sections in the spinner = 5

  Sections having Odd numbers = 3

  Sections having Even numbers =2

  We know that , [tex]\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}[/tex]

  So , probability of hitting an odd number = [tex]\dfrac{3}{5}[/tex]

  Probability of hitting an even number = [tex]\dfrac{2}{5}[/tex]

  Since all events are independent of each other ,

  So , probability of hitting an odd number three times = [tex](\dfrac{3}{5})^3=\dfrac{27}{125}[/tex]

  Probability of hitting an even number three times = [tex](\dfrac{2}{5})^3=\dfrac{8}{125}[/tex]

  Divide  [tex]\dfrac{27}{125}[/tex] by [tex]\dfrac{8}{125}[/tex] , we get

  [tex]\dfrac{27}{125}\div\dfrac{8}{125}\\\\=\dfrac{27}{125}\times\dfrac{125}{8}=\dfrac{27}{8}=3\dfrac{3}{8}[/tex]

  Hence, the probability of hitting an odd number three times is [tex]3\dfrac{3}{8}[/tex] times more than the probability of hitting an even number 3 times.

• shelbygilliland:

  Answer:

  3.375

  Step-by-step explanation: