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Factor completely 2x^3+6x^2+2x+6

  • choixongdong: 2x^3+6x^2+2x+6
    = 2(
    x^3 + 3x^2 + x +  3)
    = 2[x^2 (x + 3) + (x + 3)]
    = 2(x^2 + 1)(x + 3)

    hope it helps
  • : f(-3) = 2*-27 + 6*9 + 2*-3 + 6 =  0

    so x + 3 is a factor

    dividing the function by x + 3  gives the quotient 

    2x^2 + 2   = 2 (x^2 + 1)

    So the factors are 2(x^2 + 1)(x + 3)  Answer
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