A ball is thrown into the air with an upward velocity of 32 ft/s. Its height h in feet after t seconds is given by the function h = –16t2 + 32t + 6. a. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. b. What is the ball’s maximum height?

• MANNYCARRILLO6: if you graph it you can see what the max height is
  
  but how do you show it 
  
  well do you know what a derivative is?
  h=-32t + 32 + 0
  
  t= 1
  
  then plug into h(1)= -16(1)^2 + 32(1)+ 6
  max height is 22
  
  if you dont, then i will have to solve another way