Find the product of two numbers whose sum is 11 and difference is 3.

• bunni1400: all you would do is minus what you have, like 11-3= 8 which would be 8+3=11 and 11-8=3 which means now you have the sum of 11 and the difference of 3.
• onyebuchinnaji:

  The two numbers are 7 and 4

  Let the first number = x

  let the second number = y

  The sum of the numbers is 11, in algebra form x + y  = 11

  The difference of the two numbers is 3, in algebra form, x - y = 3

  To obtain the two unknown numbers, we solve the two equations;

  from the first equation, x = 11 - y

  substitute the value of x into the last equation;

  (11 - y) - y = 3

  11 - y - y = 3

  11 - 2y = 3

  2y = 11 - 3

  2y = 8

  y = 4

  The value of x = 11 - 4 = 7

  Thus, the two numbers are 7 and 4

  Learn more here: https://brainly.com/question/16889590